Question #1706

Why not M/P?

Started by jbenav246@gmail.com · started 2021-01-12 21:11 · last activity 2022-02-12 06:13 · 4 replies

I understand that the instructor got the answer C from looking at the previous hypothetical, but in the pervious hypothetical I further placed P 'in' due to the 6th rule saying M and P cannot be together. Based off this rule, wouldn't D be the right answer, because if they cannot be together, as in not both, then wouldn't at least one variable be out, and the other in?

Replies

  1. shunhe · 2021-01-13 22:20

    Hi @jbenav246@gmail.com, Thanks for the question! Well, let’s say we keep M and P out. So remember, the rule relating M and P says that both cannot be selected. But that doesn’t mean that one has to be selected. They could both be not selected. Basically, we diagram that rule M —> ~P P —> ~M So ~M and ~P doesn’t trigger either of these conditionals here. With M and P out, we also have to kick out J because of the second to last rule. So J, M, and P are out. That leaves F, G, K, Q, R, and S. We need to pick 5 out of 6 of these people to be in. And there are a number of ways to do that that will satisfy the rules. Consider, for example, FGK from the tenants, and QR from the homeowners. Since we can have both M and P out, it’s not the correct answer. Hope this helps! Feel free to ask any other questions that you might have.

  2. Dredd · 2021-12-26 02:20

    I had a game board with Jm, RSQ which doesn't violate the rules but seems to suggest an example contrary to the correct answer.

  3. Dredd · 2021-12-26 02:20

    never mind I re read the question

  4. Ravi · 2022-02-12 06:13

    Happy to see you got things squared away!

Sign in to reply.