Question 4 on Game 3

@Samir-Ghani, That's correct, three of the talks must have two employees. The question tells us that Q is the only employee to attend L, meaning we have four more talks - F G H I that are each attended not more than twice by Q R S T, thus we do have 2-2-2-1-1 scenario as you correctly identified. If Q attends L, we can infer that R must attend F and I since R cannot attend G, H, or L per the rules. If R attends F, we can infer that S must attend F as well per the rules. Now, we know that Q attends the first talk that T attends per the rules and Q attends neither F nor H, we can infer that Q must attend G since Q&T must go together, and we only have one spot open in I. Since S and T cannot attend the same talks, we can infer that one of them must attend H and one must attend I in either order. Thus, we can conclude that the only answer that could be false is (D) S could attend I instead, and T attend H in that scenario. F: R S G: Q T H: /S/T I: R /S/T L: Q Let me know if you have any further questions.