How did you know

Please respond

@Jessica-Killeen, Happy to help! We know that those 7 configurations are the only 7 that can exist because of our 2 rules: 1) Max 3 cleanings 2) M in 5 _ _ _ _ M _ _ The most important inference to draw in this game is that if there are 3 M pieces and 4 S pieces AND we can only have a maximum of 3 cleanings, then the M pieces cannot be spaced out individually because if they were (as in, if they were in 1, 3, 5, and 7), then there would be way too many cleanings. From this, we know that the M pieces need to either go in a block (MMM) or in a block of two and a single (MM with the the other M somewhere). You're right, this inference can take some time, but the benefit of figuring it out and creating those boards is that the questions will go by very fast. We can answer this question without making all the different scenarios. Let's see how that looks. The question asks, "if the cargo bed is cleaned exactly twice, which one of the following must be true?" If there are two cleanings, then we know that there must be three separate clusters of loads. The important thing about this additional premise is that because we know there are only 2 cleanings, we cannot have two groups of M clusters because that would require a minimum of three clusters. In other words, we can't have MM and M somewhere else. Thus, we now know that the Ms all have to be together. What's more, we know the Ms can't go in 5 through 7 because if they did, then there would only be 1 cleaning. From this, we know the Ms are either in 3 through 5 or 4 through 6. _ _ M M M _ _ _ _ _ M M M _ (A) says that "the second load is stone." We know this must be true given that we've placed all of the Ms already in this scenario (with two cleanings), so yes, the second load must be stone. (A) is the correct answer choice. Does this make sense? Let us know if you have any more questions!