Question #1852

Rule Combination is Baffling

Started by iHAVE33FLAWSandAcommonLSATflawAINTone · started 2024-04-10 05:29 · last activity 2024-04-11 03:40 · 2 replies

I am having a hard time understanding how O could be anywhere but 8. Combining rules 4, 5, and 6 creates a chain that indicates there is.. [H-?-J] & [K-?-?-L] before O. How does the setup show three options if seven of the eight must be before O?

Replies

  1. Emil-Kunkin · 2024-04-10 14:15

    I think you're missing one key possibility here: we could combine the K and the H blocks. We could have HKJ_L before O, which leaves room for O to go 6 or 7, not just 8.

  2. iHAVE33FLAWSandAcommonLSATflawAINTone · 2024-04-11 03:40

    The sound you just heard was me slapping my forehead. Thanks again!

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