hypothetical
Started by
emallas
· started 2020-06-25 23:07
· last activity 2020-06-26 00:13
· 1 reply
How is the hypothetical set up correct because don't L and Z have to both be AM or both be PM. Here L is AM but Z will be PM.
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BenMingov
· 2020-06-26 00:13
Hi Emallas, thanks for the question.
If we diagram the conditional statement, we get the following
Zam-> Lam
Lpm-> Zpm
What you find is that this looks as if it is saying that Z and L are always together. However, upon closer inspection, we could have the necessary condition occur without the sufficient condition, as with any other regular conditional statement. This would be Lam and Z not in the am (PM). This is what we have in this hypothetical and it doesn't violate the original rule. You can think of it in the following way: we have Zpm which does not trigger any rule.
I hope this helps. Please let me know if you have any other questions.
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