hypothetical

Started by emallas · started 2020-06-25 23:07 · last activity 2020-06-26 00:13 · 1 reply

How is the hypothetical set up correct because don't L and Z have to both be AM or both be PM. Here L is AM but Z will be PM.

Replies

  1. BenMingov · 2020-06-26 00:13

    Hi Emallas, thanks for the question. If we diagram the conditional statement, we get the following Zam-> Lam Lpm-> Zpm What you find is that this looks as if it is saying that Z and L are always together. However, upon closer inspection, we could have the necessary condition occur without the sufficient condition, as with any other regular conditional statement. This would be Lam and Z not in the am (PM). This is what we have in this hypothetical and it doesn't violate the original rule. You can think of it in the following way: we have Zpm which does not trigger any rule. I hope this helps. Please let me know if you have any other questions.

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