Question #1736

Question about Game Set Up

Started by Khalid-Aboujamous · started 2019-10-25 00:02 · last activity 2021-04-25 05:24 · 3 replies

Is there any situation in which L could be at S. Looking at the rules if L is at S then both N and P are at R. If N is at R then so is O. If P is at R then O is at S. This is a binary question so O could not be at both R and S. Could we then place L in R from the start or am I missing something? Thanks for your help in advance!

Replies

  1. Irina · 2019-10-25 04:46

    @Khalid-Aboujamous, Great catch! Yes, it is impossible for L to be at S, it must always be at R. It is an odd inference considering we have if L is at S..rule, but this logical chain leads to a contradiction as you have correctly identified, so we can conclude that L is at R from the start. Let me know if you have any further questions.

  2. Khalid-Aboujamous · 2019-10-25 19:53

    I was afraid I was missing something. Thanks for the clarification Irina!

  3. jkarm · 2021-04-25 05:24

    I had same question, kept getting this contradiction when I was trying to set the game up and was concerned I was doing something wrong. I am glad to know that I was correct, but now I’m worried... does LSAC do this often??

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