Question #9
Started by
vladimir-prohoroff
· started 2021-10-24 23:25
· last activity 2022-01-23 19:50
· 1 reply
I need a bit of clarification rule. Rule 1 states if G then no H/Y.
If y is selected then we can't have H/G because that's contrapositive. So I guessed E as the correct answer because we are left with JKL
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Jay-Etter
· 2022-01-23 19:50
Your contrapositive here is correct.
We would write this rule as G(f) IN -> H(f) and Y(p) OUT
Contrapositive: H(f) or Y(p) IN -> G(f) OUT.
However, E isn't the correct answer here because the question is asking us which couldn't work as the group of fish. With E, we could have
IN:J(f) K(f) L(f) W(p) X(p)
OUT: G(f) H(f) Y(p) Z(p)
This game works and doesn't violate any of the rules, so E does work and we can therefore eliminate it.
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