Question #1631

Would not both D and E be correct?

Started by Chulitazo · started 2014-11-17 04:11 · last activity 2022-06-28 00:31 · 3 replies

In the sixth question of this game, can it not be deduced, based on the assumption that I have my set-up correct, the following places for the seven houses: 1 2 3 4 5 6 7 ____ ____ ____ ____ ____ ____ ____ N R M K O/P O/L/P O/L Rules I. R neither 1 nor 7 II. not M3 - > M5 not M5 - > M3 III. MK/KM > P > L In this case, D is obviously the correct answer since the Newmans are next to the Rutans, however, no matter what, the Owens also must be next to the Piatts according to the above deduction. On the other hand, would I be wrong since this layout is a possibility?: 1 2 3 4 5 6 7 ___ ___ ___ ___ ___ ___ ___ N R M K P L O I think I may have answered my own question.

Replies

  1. Naz · 2014-11-19 00:19

    You can access the video explanation for this game by pressing the "play" button on the screen. Hope that clears things up! Please let us know if you have any other questions.

  2. NULL · 2022-05-31 00:48

    There's no complete video explanation for this question, please advise

  3. Emil-Kunkin · 2022-06-28 00:31

    Hi, We know that K=4, M is next to K, and that K,M > P >L. _ _ _ K _ _ _ We are also told that O is now after K, so we know that some combination of O, P, and L are in the final three slots. This means that R, M, and N are in the first three. Since we know that K is next to M, we know that M is three, and that R is not first, R must be two, and thus N must be one. So, N R M K _ _ _ Thus, N and R must be next to each other.

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