Combing a most quantifier with an S&N

Started by Shirnel · started 2020-04-02 05:47 · last activity 2020-04-13 17:23 · 3 replies

I've come across most quatifier and S&N like this and uncertain how to combine them. Here is an example: A most B B==>C Do I combine this as A most B ==> C to infer A most C or A some C Sorry I couldn't remember doing this in the drills.

Replies

  1. shunhe · 2020-04-02 20:53

    Hi @Shirnel, Thanks for the question! Yes, if we know for a matter of fact that A most B, and that B necessarily implies C, then we also know that A most C. Let me try to illustrate this with an example. Most donuts are sweet. If something is sweet, then it must have sugar. Well, then we know that most donuts have sugar. And if we diagram this out: D = donut S = sweet Su = sugar D most S S —> Su And from this, we conclude D most Su. Hope this helps! Feel free to ask any other questions that you might have.
  2. Shirnel · 2020-04-05 23:26

    It does, thank you.
  3. shunhe · 2020-04-13 17:23

    Glad I could help.

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