Diagram Pls.

Let's diagram: "Most serious students are happy students." Q1: SS-most-HS HS-some-SS "most serious students go to graduate school." Q2: SS-most-GS GS-some-SS "Furthermore, all students who go to graduate school are overworked." P1: GS ==> OW not OW ==> not GS So, we know that we cannot combine a "most" statement with a "some" statement. And we can only combine a Sufficient & Necessary statement with a Quantifier statement if the sufficient condition of the Sufficient & Necessary statement and the right-hand-side variable of the Quantifier statement are the same. Therefore, we can combine "Q2" and "P1," like so: SS-most-GS ==> OW to conclude: SS-most-OW, i.e. most serious students are overworked. However, as you can see, none of the answer choices give us: "SS-most-OW." Well, what else can we combine? We know that we can combine two "most" statements if their left-hand-side variables are the same into a "some" statement with their respective right-hand-side variables. So, we can combine "Q1: SS-most-HS" with the new inference: "SS-most-OW," to conclude: "HS-some-OW," i.e. some happy students are overworked, which is answer choice (B): "Some happy students are overworked." Hope that clears things up! Please let us know if you have any other questions.

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Could we have combined Q1 and Q2 straight off the bat, since they are both most and both have SS on the left to state that HS -some-GS, therefore HS -some -GS ==>OW; HS-some-OW?

@brenthorn absolutely! P: SS-most-HS P: SS-most-GS C; HS-some-GS GS-some-HS Unfortunately, this was not an answer choice but it is definitely a valid deduction. Notice, however, that this deduction is then combined with the S & N statement to arrive at the correct answer choice here: HS-some-GS ==> OW HS-some-OW This is exactly what (B) says, i.e. "Some happy students are overworked." Hope that helps! Keep up the great work!

How does SS-most-HS and SS-most-OW combined make "some"? Why can't it still be "SS-most-HS" SS-most-OW" = "HS-most-OW"?